Ⅰ 已知地球半徑，用c語言編寫程序求同一緯度不同經度的兩地的距離
#include<stdio.h>
#include<math.h>
int main(void)
{
float r, w, j, pi;//r表示半徑，w表示緯度，j表示經度差，緯度和經度的單位都是度，pi表示圓周率
pi=2.0*asin(1.0);
printf("請輸入地球半徑：r= ");
scanf("%f",&r);
printf("請輸入緯度 w= ");
scanf("%f",&w);
printf("請輸入兩個地點的經度差 j= ");
scanf("%f",&j);
printf("這兩個地方的距離里為: %lf\n",r*sin( (90.0-w)/180.0*pi )*( j/180.0*pi ) );
}
Ⅱ 求C語言程序代碼
// Microsoft Visual C++ 2010學習版
#include <stdio.h>
double add_thickness(double *thickness_ptr, int *times_ptr)
{
*thickness_ptr *= 2;
if (*times_ptr == 1)
{
return *thickness_ptr;
}
(*times_ptr)--;
return add_thickness(thickness_ptr, times_ptr);
}
int main()
{
double thickness = 0.006; // 0.006cm
int times = 43;
printf("設定紙張厚度：%f cm ", thickness);
printf("算出地月距離：%f cm ", add_thickness(&thickness,×));
printf("算出地月距離：%f km ", thickness / 1000 / 100);
// 地月距離
double distance = (double)386000 * 1000 * 100; // cm
// 操作43次
for (int i = 1; i <= 43; i++)
{
distance /= 2;
}
printf("紙張厚度應為：%f cm ", distance);
// 檢驗add_thickness()正確性
times = 43;
printf("按上述厚度，地月距離：%f km ", add_thickness(&distance,×) / 1000 / 100);
return 0;
}
---
若紙厚度0.006cm，按題操作43次，紙高度遠大於地月距離386000公里！
若紙厚度0.004388cm，按題操作43次，紙高度等於地月距離386000公里。
程序執行結果：
Ⅲ 求高手幫我做一下這道c語言編程題目
#include <stdio.h>
#include <math.h>
#define PI 3.14 //圓周率
#define RAD 6371 //地球半徑
int main()
{
double peri; //小圓周長
double rad; //小圓半徑
double length;
double longitudeA , longitudeB; //A,B經度
double latitude; //A,B緯度
double temp;
printf("請輸入A和B的經度：\n");
scanf("%lf%lf",&longitudeA,&longitudeB);
printf("請輸入A和B的緯度：\n");
scanf("%lf",&latitude);
rad = cos(latitude) * RAD;
peri = 2*PI*rad;
temp = longitudeA - longitudeB;
length = (temp >0 ? temp : (temp*-1))/360 * peri;
printf("A和B的距離是：%f千米\n",length);
return 0;
}
Ⅳ 月球圍繞地球,地球圍繞太陽的C語言代碼
A、當地球繞太陽公轉從B到C，太陽直射點由赤道向南回歸線移動，淮安的白晝越來越短，故不符合題意；B、當地球繞太陽公轉從B到C，太陽直射點由赤道向南回歸線移動，淮安的西北季風越來強盛，故不符合題意；C、當地球繞太陽公轉從B到C，太陽直射點由赤道向南回歸線移動，時間從9月23日到12月22日，梅雨時間一般在6月下旬到7月上旬，故不符合題意；D、當地球繞太陽公轉從B到C，太陽直射點由赤道向南回歸線移動，淮安的黑夜越來越長，故正確．故選：D．
Ⅳ 已知地球的平均半徑為6371.393千米，假設在地球的某一緯度上，有兩個處於不同經度的點A、B，用C語言編程
float 數 只能輸出小數點後六位..用 double, %lf定義數和輸出數
Ⅵ 地球與月球之間的距離大約是238857英里寫C語言程序在屏幕上顯示出地球與月球之間的大約是多少公里
#include<stdio.h>
main()
{
doublea=238857;
printf("%lf",a*1.609);
}
如圖所示，望採納。。。。。。
Ⅶ 已知地球任意兩點，求兩點間的直線距離和球面距離用c語言
這段代碼可以達到你的目的。注釋和其他有關信息自己添加。
//#include "stdafx.h"//vc++6.0加上這一行.
#include "stdio.h"
#include "math.h"
void main(void){
double x1,x2,x,r=6378.137,pai=3.1415926;
printf("Type 2 longitudes\n");
scanf("%lf%lf",&x1,&x2);
while(x1<0) x1+=360;
while(x2<0) x2+=360;
if((x=fabs(x1-x2))>180) x=360-x;
x=x/360*2*pai;
printf("The linear distance is %f(km)\n",2*r*sin(x/2));
printf("The arc length is %f(km)\n",r*x);
}
Ⅷ 利用日期、經緯度求日出日落時間 C語言程序代碼
#definePI3.1415926
#include<math.h>
#include<iostream>
usingnamespacestd;
intdays_of_month_1[]={31,28,31,30,31,30,31,31,30,31,30,31};
intdays_of_month_2[]={31,29,31,30,31,30,31,31,30,31,30,31};
longdoubleh=-0.833;
//定義全局變數
voidinput_date(intc[]){
inti;
cout<<"Enterthedate(form:20090310):"<<endl;
for(i=0;i<3;i++){
cin>>c[i];
}
}
//輸入日期
voidinput_glat(intc[]){
inti;
cout<<"Enterthedegreeoflatitude(range:0°-60°,form:404040(means40°40′40″)):"<<endl;
for(i=0;i<3;i++){
cin>>c[i];
}
}
//輸入緯度
voidinput_glong(intc[]){
inti;
cout<<"Enterthedegreeoflongitude(westisnegativ,form:404040(means40°40′40″)):"<<endl;
for(i=0;i<3;i++){
cin>>c[i];
}
}
//輸入經度
intleap_year(intyear){
if(((year%400==0)||(year%100!=0)&&(year%4==0)))return1;
elsereturn0;
}
//判斷是否為閏年:若為閏年，返回1；若非閏年，返回0
intdays(intyear,intmonth,intdate){
inti,a=0;
for(i=2000;i<year;i++){
if(leap_year(i))a=a+366;
elsea=a+365;
}
if(leap_year(year)){
for(i=0;i<month-1;i++){
a=a+days_of_month_2[i];
}
}
else{
for(i=0;i<month-1;i++){
a=a+days_of_month_1[i];
}
}
a=a+date;
returna;
}
//求從格林威治時間公元2000年1月1日到計算日天數days
longdoublet_century(intdays,longdoubleUTo){
return((longdouble)days+UTo/360)/36525;
}
//求格林威治時間公元2000年1月1日到計算日的世紀數t
longdoubleL_sun(longdoublet_century){
return(280.460+36000.770*t_century);
}
//求太陽的平黃徑
longdoubleG_sun(longdoublet_century){
return(357.528+35999.050*t_century);
}
//求太陽的平近點角
longdoubleecliptic_longitude(longdoubleL_sun,longdoubleG_sun){
return(L_sun+1.915*sin(G_sun*PI/180)+0.02*sin(2*G_sun*PI/180));
}
//求黃道經度
longdoubleearth_tilt(longdoublet_century){
return(23.4393-0.0130*t_century);
}
//求地球傾角
longdoublesun_deviation(longdoubleearth_tilt,longdoubleecliptic_longitude){
return(180/PI*asin(sin(PI/180*earth_tilt)*sin(PI/180*ecliptic_longitude)));
}
//求太陽偏差
longdoubleGHA(longdoubleUTo,longdoubleG_sun,longdoubleecliptic_longitude){
return(UTo-180-1.915*sin(G_sun*PI/180)-0.02*sin(2*G_sun*PI/180)+2.466*sin(2*ecliptic_longitude*PI/180)-0.053*sin(4*ecliptic_longitude*PI/180));
}
//求格林威治時間的太陽時間角GHA
longdoublee(longdoubleh,longdoubleglat,longdoublesun_deviation){
return180/PI*acos((sin(h*PI/180)-sin(glat*PI/180)*sin(sun_deviation*PI/180))/(cos(glat*PI/180)*cos(sun_deviation*PI/180)));
}
//求修正值e
longdoubleUT_rise(longdoubleUTo,longdoubleGHA,longdoubleglong,longdoublee){
return(UTo-(GHA+glong+e));
}
//求日出時間
longdoubleUT_set(longdoubleUTo,longdoubleGHA,longdoubleglong,longdoublee){
return(UTo-(GHA+glong-e));
}
//求日落時間
longdoubleresult_rise(longdoubleUT,longdoubleUTo,longdoubleglong,longdoubleglat,intyear,intmonth,intdate){
longdoubled;
if(UT>=UTo)d=UT-UTo;
elsed=UTo-UT;
if(d>=0.1){
UTo=UT;
UT=UT_rise(UTo,GHA(UTo,G_sun(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))),glong,e(h,glat,sun_deviation(earth_tilt(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo))))));
result_rise(UT,UTo,glong,glat,year,month,date);
}
returnUT;
}
//判斷並返回結果（日出）
longdoubleresult_set(longdoubleUT,longdoubleUTo,longdoubleglong,longdoubleglat,intyear,intmonth,intdate){
longdoubled;
if(UT>=UTo)d=UT-UTo;
elsed=UTo-UT;
if(d>=0.1){
UTo=UT;
UT=UT_set(UTo,GHA(UTo,G_sun(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))),glong,e(h,glat,sun_deviation(earth_tilt(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo))))));
result_set(UT,UTo,glong,glat,year,month,date);
}
returnUT;
}
//判斷並返回結果（日落）
intZone(longdoubleglong){
if(glong>=0)return(int)((int)(glong/15.0)+1);
elsereturn(int)((int)(glong/15.0)-1);
}
//求時區
voidoutput(longdoublerise,longdoubleset,longdoubleglong){
if((int)(60*(rise/15+Zone(glong)-(int)(rise/15+Zone(glong))))<10)
cout<<"Thetimeatwhichthesunrisesis"<<(int)(rise/15+Zone(glong))<<":0"<<(int)(60*(rise/15+Zone(glong)-(int)(rise/15+Zone(glong))))<<". ";
elsecout<<"Thetimeatwhichthesunrisesis"<<(int)(rise/15+Zone(glong))<<":"<<(int)(60*(rise/15+Zone(glong)-(int)(rise/15+Zone(glong))))<<". ";
if((int)(60*(set/15+Zone(glong)-(int)(set/15+Zone(glong))))<10)
cout<<"Thetimeatwhichthesunsetsis"<<(int)(set/15+Zone(glong))<<":"<<(int)(60*(set/15+Zone(glong)-(int)(set/15+Zone(glong))))<<". ";
elsecout<<"Thetimeatwhichthesunsetsis"<<(int)(set/15+Zone(glong))<<":"<<(int)(60*(set/15+Zone(glong)-(int)(set/15+Zone(glong))))<<". ";
}
//列印結果intmain(){
longdoubleUTo=180.0;
intyear,month,date;
longdoubleglat,glong;
intc[3];
input_date(c);
year=c[0];
month=c[1];
date=c[2];
input_glat(c);
glat=c[0]+c[1]/60+c[2]/3600;
input_glong(c);
glong=c[0]+c[1]/60+c[2]/3600;
longdoublerise,set;
rise=result_rise(UT_rise(UTo,GHA(UTo,G_sun(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))),glong,e(h,glat,sun_deviation(earth_tilt(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))))),UTo,glong,glat,year,month,date);
set=result_set(UT_set(UTo,GHA(UTo,G_sun(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))),glong,e(h,glat,sun_deviation(earth_tilt(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))))),UTo,glong,glat,year,month,date);
output(rise,set,glong);
system("pause");
return0;
}