『壹』 sql查詢中如何剔除重復
1，存在兩條完全相同的紀錄
這是最簡單的一種情況，用關鍵字distinct就可以去掉
example： select distinct * from table(表名) where (條件)
2，存在部分欄位相同的紀錄（有主鍵id即唯一鍵）
如果是這種情況的話用distinct是過濾不了的，這就要用到主鍵id的唯一性特點及group by分組
example:
select * from table where id in (select max(id) from table group by [去除重復的欄位名列表,....])
3，沒有唯一鍵ID
example:
select identity(int1,1) as id,* into newtable(臨時表) from table
select * from newtable where id in (select max(id) from newtable group by [去除重復的欄位名列表,....])
drop table newtable
(1)sql查詢重復id擴展閱讀
1、查找表中多餘的重復記錄，重復記錄是根據單個欄位（peopleId）來判斷
select * from people
where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)
2、刪除表中多餘的重復記錄，重復記錄是根據單個欄位（peopleId）來判斷，只留有rowid最小的記錄
delete from people
where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)
and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)
3、查找表中多餘的重復記錄（多個欄位）
select * from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
『貳』 sql怎麼查詢兩個欄位相同的記錄
1、查詢重復的數據，只查詢重復記錄，不管其餘信息，如ID什麼的：
1selectuid,timefromztestGROUPBYuid,timehavingcount(*)>1;
查出結果讓春是
uid time
1 1
『叄』 求sql多表查詢重復數據語法
Create Table tablea(Id Number(12));
Create Table tableb(Id Number(12));
Create Table tablec(Id Number(12));
Insert Into tablea Values(1);
Insert Into tablea Values(2);
Insert Into tablea Values(3);
Insert Into tableb Values(3);
Insert Into tableb Values(4);
Insert Into tableb Values(5);
Insert Into tablec Values(5);
Insert Into tablec Values(6);
Insert Into tablec Values(7);
Commit;
select Id,Count(*) cnt from (
select id from tableA
union all
select id from tableB
union all
select id from tableC ) t Group By Id Having Count(*)>1;
『肆』 sql查找重復多次的數據
直接查出重復
--查出表中有重復的id的記錄，並計算相同id的數量
select id,count(id) from @table group by id having(count(id)>1)
其中，group by id，是按id欄位分組查詢：
select id,count(id) from @table group by id
可以得到各不同id的數量合計
having(count(id)>1)判斷數量大於1，也就是有重復id的記錄