當前位置:首頁 » 編程語言 » c語言萬年歷節假日
擴展閱讀
webinf下怎麼引入js 2023-08-31 21:54:13
堡壘機怎麼打開web 2023-08-31 21:54:11

c語言萬年歷節假日

發布時間: 2023-07-16 01:11:21

1. 用c語言設計一個簡單的萬年歷怎麼寫代碼

#include"stdio.h"#include"stdlib.h"main(){intYear,Month;//年、月intFirstDay_Year,FirstDay_Month;//某年的第一天是星期幾,某年某月的第一天是星期幾(范圍是0~6,其中0代表星期日)intIsLeapYear;//是否為閏年,0表示不是閏年,1表示是閏年inti,d,y;//臨時變數charYN;//YesNo,程序是否要繼續intDays[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};//Days[1~12]存儲每個月有多少天,其中二月的天數是可變的(閏年29天,平年28天),這里初始化為28天printf("C語言簡單萬年歷\n");//列印標題XunHuan://循環標號(可以通過goto跳轉到這里)printf("請輸入年份:");//提示輸入年份(0~9999)scanf("%d",&Year);//把輸入的年份賦值給變數Yearprintf("請輸入月份:");//提示輸入月份(1~12)scanf("%d",&Month);//把輸入的月份賦值給變數Monthy=Year;FirstDay_Year=5*(y/4)+(y%4)-(y/100)+(y/400);//蔡勒公式(計算某年的第一天是星期幾)IsLeapYear=(y%4==4&&y%100!=100||y%400==0)?1:0;//判斷是否為閏年Days[2]=(IsLeapYear==1)?29:28;//閏年二月29天,非閏年二月28天for(i=1,d=0;i

2. C語言程序設計萬年歷

#include
<stdio.h>
int
leap
(int
year)
{if(year%4==0&&year%100!=0||year%400==0)
//判斷是否是閏年
return
1;
else
return
0;
}
int
days_month
(int
month,int
year)
//判斷大月和小月
{
if(month==1||month==3||month==5||month==7||month==8||month==10||month==12)
//找出大月
return
31;
if(month==4||month==6||month==9||month==11)
//找出小月
return
30;
if(month==2&&leap(year)==1)
return
29;
//判斷二月是29天還是29天
else
return
28;
}
int
firstday(int
month,int
year)
{int
w;
w=(1+2*month+3*(month+1)/5+year+year/4+year/400-year/100)%7+1;
//判斷每個月開始的第一天是星期幾
return
w;
}
main()
{int
i,j=1,k=1,a,b,month,year;
printf("\n
input
month
and
year:\n");
scanf("%d%d",&month,&year);
//輸入月和年
b=days_month(month,year);
a=firstday
(month,year);
printf("
Sun
Mon
Tue
Wed
Thu
Fri
Sat
\n");
//輸出對應當月的日歷
if(a==7)
{for(i=1;i<=b;i++)
{printf("%4d",i);
if(i%7==0)
{printf("\n");
}
}
}
if(a!=7)
{while
(j<=4*a)
{printf("
");
j++;
}
for(i=1;i<=b;i++)
{printf("%4d",i);
if(i==7*k-a)
{printf("\n");
k++;
}
}
}
printf("\n");
}

3. 萬年歷C語言

// 萬年歷.cpp : Defines the entry point for the console application.
// 顯示1900年以後任何年份的日歷,日歷以月份順序排列,每月以星期順序排列。
//採用一般日歷計算方法,先給出一般年份的每月天數,如果是閏年,第二個月天數為29,再計算出制定年份的1月1日是星期幾,然後根據這些數據
//計算出全年日歷,邊計算邊顯示。
//函數leap()判定是否閏年
//函數week()計算year年份的1月1日是星期幾。計算方法是,已知1900年1月1日是星期一,先計算從1900年到year年份的前一年一共有多少(s)天,
//則(s+1)%7為年份year的1月1日的星期號。
#include "stdafx.h"
#include <iostream>
#include <iomanip>
#include <string>
using namespace std;
static char *week0=" SUN MON TUE WED SUR FRI SAT"; //指針形式定義一個字元串,或者是week0[36]
int leap(int year)
{
if((year%4==0 && year%100!=0)|| year%400==0)
return 1;
else return 0;
}

int week(int year)
{
int i,w;
int s=0;
for(i=1900;i<year;i++)
{
if(leap(i))
s+=366;
else s+=365; //計算從1900年到year年的天數
}
w=(s+1)%7;
return w;
}

void main()
{
int month[12]={31,28,31,30,31,30,31,31,30,31,30,31};
int i,j,k;
int year;
int w;
do
{
cout<<"輸入年份:";
cin>>year;
}while(year<=1900);
w=week(year);
if(leap(year))
month[1]=29;
for(i=0;i<12;i++)
{
for(k=0;k<35;k++)
cout<<"_"; //輸出一條橫線
cout<<endl;
cout<<setw(20)<<i+1<<"月"<<endl;
cout<<endl;
cout<<week0<<endl;
for(k=0;k<w;k++)
cout<<" "; //輸出若干空格
for(j=1;j<=month[i];j++)
{
if((j+w)%7==1) //遇到星期日時,換一行輸出
cout<<endl;
cout<<setw(5)<<j;
}
cout<<endl;
for(k=0;k<35;k++)
cout<<"_"; //輸出一條橫線
cout<<endl;
w=(w+month[i])%7; //計算下個月1號是星期幾
}
cout<<endl;
system("pause");
}

4. 用C語言怎麼編寫萬年歷

C語言編寫萬年歷的源代碼如下:

#include <stdio.h>

int week(int y,int m,int d);

int main()

{

char wk[7][3] = {{"天"},{"一"},{"二"},{"三"},{"四"},{"五"},{"六"}};

int year, month, day, w;

scanf("%d %d %d", &year, &month, &day);

w = week(year, month, day);

printf("%d年%d月%d日 星期%s", year, month, day, wk[w]);

}

int week(int y,int m,int d)

{

static int r[13]={0,0,3,3,6,1,4,6,2,5,0,3,5};

int c,w;

y %= 400;

if ((y==0||y%4==0&&y%100!=0)&&m<3)

c = 5;

else

c = 6;

w = (y+y/4-y/100+r[m]+d+c)%7;

return w;

}

(4)c語言萬年歷節假日擴展閱讀

電子時鍾C語言版的源代碼如下:

#include<stdio.h>

#include<time.h>

#include<string.h>

int main()

{

char str[50];

time_t t;

struct tm *nt;

while(1)

{

system("cls");//清屏函數

t=time(NULL);

nt=localtime(&t);

strftime(str,50,"%Y-%m-%d %H:%M:%S 「,nt);

printf("現在時刻:%s ",str);

}

getch();

return 0;

}

5. 用C語言怎麼編寫這個萬年歷

核心演算法:星期(0~6)=(年份系數+月份系數+日期)%7;

其中,年份系數我以2007年做參照,已知2007年,年份系數是0,往前往後分別是遞減和遞增。增減規律:非閏年為±1,閏年1~2月-2或+1,閏年3~12月+2或者-1。

其中,12個月份系數對應:0,3,3,6,1,4,6,2,5,0,3,5。

根據以上規律,只要利用循環,就可以的到對應系數和星期。

日歷實現翻頁功能,按鍵盤左右方向鍵可以翻譯查看當年其他月份,按向上方向鍵可以返回菜單。

下面是代碼:

#include <stdio.h>

#include <malloc.h>

#include <string.h>

#include <conio.h>

#include <math.h>

#include <time.h>

#define XY 2007

#define X07 0//以2007年年系數0做參照

int isLeapYear(int year);//判斷是否是閏年,是返回1,否返回0

int addyx(int yx,int n);//年系數自增,0~6,n:自增的跨度,返回自增後的年系數

int getYX(int year,int month);//獲得年系數0~6

int getMX(int month);//獲得月系數

int getWeek(int yx,int mx,int day);//通過年月系數(yx:年系數;mx:月系數)及日期獲取星期

char *getStrWeek(int yx,int mx,int day);//通過年月系數(yx:年系數;mx:月系數)及日期獲取星期對應的中文字元串

int getMaxDay(int year,int month);//通過年月獲取當月最大天數

void prCalendar(int year,int month);//列印日歷

int showMeun();//列印主菜單

int getDuration(int year,int month,int day);//通過日期獲取距今天數

int calendar[6][7];

int main()

{

//int year,month,day,yx,mx;

while(1)

{

if(!showMeun())

break;

}

return 0;

}

int showMeun()//列印主菜單

{

int n,year,month,day,yx,mx;

while(1)

{

system("cls");

printf("1、輸入年份,顯示該年每個月的日歷 ");

printf("2、輸入年月,顯示該月的天數 ");

printf("3、輸入日期,顯示距離今天的天數 ");

printf("4、輸入日期,查詢這一天是星期幾 ");

printf("0、結束程序 ");

n=-1,year=0,month=0,day=0;

while(n<0 || n>4)

{

printf("請輸入選擇的菜單序號:");

scanf("%d",&n);

}

switch(n)

{

case 1:while(year<=0 || year>9999)

printf("請輸入年份:"),scanf("%d",&year);

prCalendar(year,1);

break;

case 2:while(year<=0 || year>9999 || month<=0 || month>12)

printf("請輸入年份及月份:"),scanf("%d%d",&year,&month);

printf("%4d年%2d月共有%d天 按任意鍵繼續。。。。。。 ",year,month,getMaxDay(year,month)),getch();

break;

case 3:while(year<=0 || year>9999 || month<=0 || month>12 || day<0 || day>getMaxDay(year,month))

printf("請輸入日期:"),scanf("%d%d%d",&year,&month,&day);

printf("距離今日有%d天 按任意鍵繼續。。。。。。 ",getDuration(year,month,day)),getch();

break;

case 4:while(year<=0 || year>9999 || month<=0 || month>12 || day<0 || day>getMaxDay(year,month))

printf("請輸入日期:"),scanf("%d%d%d",&year,&month,&day);

yx=getYX(year,month);

mx=getMX(month);

printf("%4d年%2d月%2d日是%s 按任意鍵繼續。。。。。。 ",year,month,day,getStrWeek(yx,mx,day)),getch();

break;

case 0:return 0;

}

}

return n;

}

void prCalendar(int year,int month)//列印日歷

{

char c1,c2;

int i,j,*p=NULL,yx,mx,cnt,w,maxDay;

while(1)

{

p=&calendar[0][0];

yx=getYX(year,month),mx=getMX(month);

cnt=0,w=getWeek(yx,mx,1);

maxDay=getMaxDay(year,month);

for(i=0;i<6;i++)

for(j=0;j<7;j++)

{

if(cnt<w)

p++,cnt++;

calendar[i][j]=0;

}

for(i=1;i<=maxDay;i++)

*p=i,p++;

system("cls");

printf(" %4d 年%2d月 ",year,month);

printf("日 一 二 三 四 五 六 ");

for(i=0;i<6;i++,printf(" "))

for(j=0;j<7;j++)

if(calendar[i][j]==0)

printf(" ");

else

printf("%2d ",calendar[i][j]);

printf("<- 按方向鍵向左或向右翻頁 -> ");

printf(" 按向上方向鍵返回主菜單 ");

c1=getch();

c2=getch();

if(c1==-32 && c2==75)//左鍵

{

if(month==1)

month=12;

else

month--;

}

if(c1==-32 && c2==77)//右鍵

{

if(month==12)

month=1;

else

month++;

}

if(c1==-32 && c2==72)//上鍵

{

showMeun();

break;

}

}

}

int getDuration(int year,int month,int day)//通過日期獲取距今天數

{

int i,y,m,d,sum=0,sum2=0,minY,maxY,minM,maxM,minD,maxD;

time_t tt;

struct tm *tmp;

time(&tt);

tmp=localtime(&tt);

y=1900+tmp->tm_year,m=1+tmp->tm_mon,d=tmp->tm_mday;//獲取當前日期的年月日

if(year<y)

minY=year,maxY=y,minM=month,maxM=m,minD=day,maxD=d;

if(year>y)

minY=y,maxY=year,minM=m,maxM=month,minD=d,maxD=day;

if(year!=y)

{

for(i=minY;i<maxY;i++)//按相差年份累加(不包含右端最大年份)

if(isLeapYear(i))

sum+=366;//閏年

else

sum+=365;

for(i=1;i<minM;i++)//扣除左端年份已過月份對應天數

sum-=getMaxDay(minY,i);

sum-=minD;//扣除左端當月已過天數

for(i=1;i<maxM;i++)//累加右端最大年份已過月份對應天數(不包含最大年份當月)

sum+=getMaxDay(maxY,i);

sum+=maxD;//累加右端當月已過天數

}

else//如果年份相同,累加兩邊一年內已過天數,求差值

{

for(i=1;i<month;i++)

sum+=getMaxDay(month,i);

sum+=day;

for(i=1;i<m;i++)

sum2+=getMaxDay(m,i);

sum2+=d;

return abs(sum2-sum);

}

return sum;

}

int getMaxDay(int year,int month)//通過年月獲取當月最大天數

{

int days[12]={31,28,31,30,31,30,31,31,30,31,30,31};

if(isLeapYear(year) && month==2)

return days[month-1]+1;

return days[month-1];

}

char *getStrWeek(int yx,int mx,int day)//通過年月系數(yx:年系數;mx:月系數)及日期獲取星期對應的中文字元串

{

int w;

static char week[7];

memset(week,0,7);

strcpy(week,"星期");

w=getWeek(yx,mx,day);

switch(w)

{

case 0:strcat(week,"日");break;

case 1:strcat(week,"一");break;

case 2:strcat(week,"二");break;

case 3:strcat(week,"三");break;

case 4:strcat(week,"四");break;

case 5:strcat(week,"五");break;

case 6:strcat(week,"六");break;

}

return week;

}

int getWeek(int yx,int mx,int day)//通過年月系數(yx:年系數;mx:月系數)及日期獲取星期對應的數值0~6

{

return (yx+mx+day)%7;

}

int getMX(int month)//獲得月系數

{

int xmonth[12]={0,3,3,6,1,4,6,2,5,0,3,5};//月系數:1-12月,每月的系數。

return xmonth[month-1];

}

int getYX(int year,int month)//獲得年系數0~6

{

int yx=0,nyear=XY,isly,flag;

if(nyear==year)

return 0;

if(nyear<year)

flag=0,nyear++;

else

flag=1,nyear--;

while(1)

{

isly=isLeapYear(nyear);

if(!isly){//非閏年年系數累加1

if(!flag)

yx=addyx(yx,1);

else

yx=addyx(yx,-1);

}

if(isly && month>=1 && month<=2){//閏年1~2月年系數累加1,3`12月年系數累加2

if(!flag)

yx=addyx(yx,1);

else

yx=addyx(yx,-2);

}

else if(isly && month>=3 && month<=12){

if(!flag)

yx=addyx(yx,2);

else

yx=addyx(yx,-1);

}

if(nyear==year)

break;

if(!flag && nyear<year)

nyear++;

if(flag && nyear>year)

nyear--;

}

return yx;

}

int addyx(int yx,int n)//年系數自增,0~6,n:自增的跨度,返回自增後的年系數

{

if(n>0)

{

if(yx+n<=6)

return yx+n;

if(yx+n>6)

return yx+n-7;

}

if(n<0)

{

if(yx+n>=0)

return yx+n;

if(yx+n<0)

return yx+n+7;

}

return -1;

}

int isLeapYear(int year)//判斷是否是閏年,是返回1,否返回0

{

if((year%4==0 && year%100!=0)||(year%400==0))

return 1;

return 0;

}

6. C語言編寫萬年歷~~速度

/*C語言編程萬年歷
要求輸入年月,判斷是否閏年;
輸入年月日,判斷星期幾;
輸入年份,打出12個月的月歷;
輸入年份,月份,列印出本月日歷;
要求用多個函數實現。*/
#include<stdio.h>
#include<time.h>
#include<string.h>int calendar[12][6][7];/*月歷*/
char* week[]={"Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Satarday"};
char* Monthname[]={"January","February","March","April","May","June","July",
"August","September","October","November","December"};
int monthday[]={31,28,31,30,31,30,31,31,30,31,30,31};
char* menu[]={/*操作菜單*/
"1.Input a year number,check whether it's a leap year.\n",
"2.Input year,month,day,check the weekday.\n",
"3.Input year,month,output the calendar of that month.\n",
"4.Input year,output all the month calendar.\n",
"0.Exit.\n"
};/*判斷參數year傳遞的年份是否是閏年*/
int IsLeapyear(int year)
{
if(!(year%4)&&year%100||!(year%400)) return 1;
else return 0;
}/*輸入年月日,判斷星期幾,利用Zeller公式w=y+[y/4]+[c/4]-2c+[26(m+1)/10]+d-1
w是結果星期數,y是年份的後兩位,c是年份的前兩位,m是月份,3≤m≤14,也就是當
m≤2時,要算到前一年的13月份和14月份,最後要將w對7取模
*/
int WeekDay(int year,int month,int day)
{
int w,y,c,m,d;
c=year/100;
if(month<3){
m=12+month;
y=year%100-1;
}
else{
m=month;
y=year%100;
}
d=day;
w=y+y/4+c/4-2*c+26*(m+1)/10+d-1;
return (w%7+7)%7;
}/*輸入年份,月份,列印出本月的日歷*/
void Monthly(int year,int month)
{
int weekday,i,j;
if(month==2)
if(IsLeapyear(year)) monthday[1]+=1;
weekday=WeekDay(year,month,1);
printf("%s\n",Monthname[month-1]);
printf("Sun. Mon. Tue. Wed. Thu. Fri. Sat.\n");
for(i=1,j=weekday;i<=monthday[month-1];i++,j++){
calendar[month-1][j/7][j%7]=i;
}
for(i=0;i<6;i++){
for(j=0;j<7;j++)
{
if(calendar[month-1][i][j]==0) printf("%5c",' ');
else printf("%-5d",calendar[month-1][i][j]);
}
printf("\n");
}
}void allMonth(int year) /*輸入年份,列印出12個月的月歷*/
{
int i;
for(i=1;i<=12;i++){
Monthly(year,i);
getch();/*按任意鍵繼續執行*/
}
}void main(void)
{
int year,month,day,i,n,weekday;
memset(&calendar,sizeof(calendar),0); /*初始化月歷*/
for(i=0;i<5;i++)
printf("%s",menu[i]);
while(1){
printf("Please choose the menu:");
scanf("%d",&n);
printf("\n");
switch(n){
case 1:
printf("Please input year:");
scanf("%d",&year);
if(IsLeapyear(year)) printf("\n%d is leap year.\n",year);
else printf("%d isn't leap year.\n",year);
break;
case 2:
printf("Please input year month day:");
scanf("%d%d%d",&year,&month,&day);
printf("\n");
weekday=WeekDay(year,month,day);
printf("That day is %s\n",week[weekday]);
break;
case 3:
printf("Please input year month,then it output a calendar of that month:");
scanf("%d%d",&year,&month);
printf("\n");
Monthly(year,month);
break;
case 4:
printf("Please input year,then it will output the calendar of that year:");
scanf("%d",&year);
printf("\n");
allMonth(year);
break;
case 0:
return;
default:
printf("The number you input is invalid.\n");
break;
}
}
getch(); /*按任意鍵,程序退出*/
}這個程序是可用的~~希望能幫到你~~~

7. 用C語言製作萬年歷

TC 2.0

/* welcome to use the WanNianLi system!
Copyright @ 2005 KongXinCai All rights reserved!:):):)*/

#include<stdio.h>
#include<stdlib.h>

char* month_str[]={"January","February","March","April","May","June","July","August","September","October","November","December"};
char* week[]={"Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"};

int IsLeapYear(int year) /*find out the year is leap year or not*/
{
if((year%4==0&&year%100!=0)||(year%400==0))
return 1;
else
return 0;

}
int month_day(int year,int month)
{
int mon_day[]={31,28,31,30,31,30,31,31,30,31,30,31};
if(IsLeapYear(year)&&month==2)
return 29;
else
return(mon_day[month-1]);

}
int DaySearch(int year,int month,int day) /*search what day this day is*/
{
int c=0;
float s;
int m;
for(m=1;m<month;m++)
c=c+month_day(year,m);
c=c+day;
s=year-1+(float)(year-1)/4+(float)(year-1)/100+(float)(year-1)/400-40+c;
return ((int)s%7);
}

int PrintAllYear(int year)/*print the all year*/
{
int temp;
int i,j;
printf("\n\n%d Calander\n",year);
for(i=1;i<=12;i++)
{
printf("\n\n%s(%d)\n",month_str[i-1],i);
printf("0 1 2 3 4 5 6 \n");
printf("S M T W T F S \n\n");
temp=DaySearch(year,i,1);
for(j=1;j<=month_day(year,i)+temp;j++)
{
if(j-temp<=0)
printf(" ");
else if(j-temp<10)
printf("%d ",j-temp);
else
printf("%d ",j-temp);

if(j%7==0)
printf("\n");
}
}
return 0;
}

int main()
{
int option,da;
char ch;
int year,month,day;
printf("Copyright @ 2005 TianQian All rights reserved!:):):)");
printf("\n\nWelcome to use the WanNianLi system!\n");

while(1)
{
printf("\nPlease select the service you need:\n");
printf("\n1 Search what day the day is");
printf("\n2 Search whether the year is leap year or not");
printf("\n3 Print the calander of the whole year");
printf("\n4 Exit\n");
scanf("%d",&option);

switch(option)
{
case 1:
while(1)
{
printf("\nPlease input the year,month and day(XXXX,XX,XX):");
scanf("%d,%d,%d,%c",&year,&month,&day);
da=DaySearch(year,month,day);
printf("\n%d-%d-%d is %s,do you want to continue?(Y/N)",year,month,day,week[da]);
fflush(stdin);
scanf("%c",&ch);
if(ch=='N'||ch=='n')
break;
}
break;
case 2:
while(1)
{
printf("\nPlease input the year which needs searched?(XXXX)");
scanf("%d",&year);
if(IsLeapYear(year))
printf("\n%d is Leap year,do you want to continue?(Y/N)",year);
else
printf("\n%d is not Leap year,do you want to continue(Y/N)?",year);
fflush(stdin);
scanf("%c",&ch);
if(ch=='N'||ch=='n')
break;
}
break;
case 3:
while(1)
{
printf("\nPlease input the year which needs printed(XXXX)");
scanf("%d",&year);
PrintAllYear(year);
printf("\nDo you want to continue to print(Y/N)?");
fflush(stdin);
scanf("%c",&ch);
if(ch=='N'||ch=='n')
break;
}
break;
case 4:
fflush(stdin);
printf("Are you sure?(Y/N)");
scanf("%c",&ch);
if(ch=='Y'||ch=='y')
exit(0);
break;
default:
printf("\nError:Sorry,there is no this service now!\n");
break;
}

}

return 0;
}