㈠ c语言编写程序,输入某年某月,求该月的天数
#include<iostream.h>
voidmain()
{
intYear,Month,Day;
cout<<"Pleaseenterthecurrentdate(年月以空格分隔):";
cin>>Year>>Month;
while(Month<=0||Month>12)
{
cout<<"输入时间有误，请重新输入：";
cin>>Year>>Month;
}
switch(Month)
{
case4:
case6:
case8:
case9:
case11:
Day=30;
break;
case2:
if(Year%400==0||Year%4==0&&nYear%100!=0)
Day=29;
else
Day=28;
break;
default:Day=31;
}
cout<<"该月天数为："<<Day<<"天";
}
㈡ 用c语言编写一程序，用户输入月份，计算该月有多少天
同意楼上几位的回答,没有年份是算不出来的.再一个要这个月有多少天?用脑子算呀!如果说有把年份一块输入的话,算这个日期之前的一年里的总天数,我这倒是有个不错的程序...
main()
{
int
day,month,year,sum,leap;
printf("\nplease
intput
year,month,day\n");
scanf("%d,%d,%d",&year,&month,&day);
switch(month)
{
case
1:sum=0;break;
case
2:sum=31;break;
case
3:sum=59;break;
case
4:sum=90;break;
case
5:sum=120;break;
case
6:sum=151;break;
case
7:sum=181;break;
case
8:sum=212;break;
case
9:sum=243;break;
case
10:sum=273;break;
case
11:sum=304;break;
case
12:sum=334;break;
default:printf("data
error");break;
}
sum=sum+day;
if(year%400==0||(year%4==0&&year%100!=0))
leap=1;
else
leap=0;
if(leap==1&&month>2)
sum++;
printf("it
is
the
%dth
day
of
the
year.",sum);
}
㈢ c语言编写程序从键盘输入年份和月份，计算出这一年的这一个月有多少天
#include<stdio.h>
int main()
{
int year,month,days,day;
printf("请输入年月日");
scanf("%d-%d-%d",&year,&month,&days);
switch(month)
{
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12: day=31;break;
case 4:
case 6:
case 9:
case 11:day=30;break;
case 2:
if(year%4==0&&year%100!=0||year%400==0)
day=29;
else
day=28;break;
default :printf("error ");
}
printf("这个月有%d天",day);
}
㈣ C语言怎样计算天数
【程序1】：
main()
{
int day,month,year,sum,leap;
printf("\nplease input year,month,day\n");
scanf("%d,%d,%d",&year,&month,&day);
switch(month)/*先计算某月以前月份的总天数*/
{
case 1:sum=0;break;
case 2:sum=31;break;
case 3:sum=59;break;
case 4:sum=90;break;
case 5:sum=120;break;
case 6:sum=151;break;
case 7:sum=181;break;
case 8:sum=212;break;
case 9:sum=243;break;
case 10:sum=273;break;
case 11:sum=304;break;
case 12:sum=334;break;
default:printf("data error");break;
}
sum=sum+day; /*再加上某天的天数*/
if(year%400==0||(year%4==0&&year%100!=0))/*判断是不是闰年*/
leap=1;
else
leap=0;
if(leap==1&&month>2)/*如果是闰年且月份大于2,总天数应该加一天*/
sum++;
printf("It is the %dth day.",sum);}