㈠ 如何用sql语句查询各门课程的平均成绩
创建表：
SET ANSI_NULLS ONGOSET QUOTED_IDENTIFIER ONGOSET ANSI_PADDING ONGOCREATE TABLE [dbo].[stuscore]
( [name] [varchar](50) COLLATE Chinese_PRC_CI_AS NULL,
[subject] [varchar](50) COLLATE Chinese_PRC_CI_AS NULL,
[score] [int] NULL,
[stuid] [int] NULL)
ON [PRIMARY]
GO
SET ANSI_PADDING OFF
插入数据：
insert into dbo.stuscore values ('张三','数学',89,1)；
insert into dbo.stuscore values ('张三','语文',80,1)；
insert into dbo.stuscore values ('张三','英语',70,1)；
insert into dbo.stuscore values ('李四','数学',90,2)；
insert into dbo.stuscore values ('李四','语文',70,2)；
insert into dbo.stuscore values ('李四','英语',80,2)；
查询结果如下：
列出各门课程的平均成绩：
select subject,AVG(score)平均成绩 from stuscore
group by subject;
㈡ sql 怎么求出个人三科平均分 语文数学英语 学生有10个 用一条语句输出个人3科平均分！
select [姓名]，[语文],[数仔余早学],[英语],([语文]+[数念雀学]+[英语])/3.0 from [成绩表] where [姓名毁兆]='张三'
㈢ SQL 查询 问题
select a.Sname '姓名'知含派,b.Cname '老桐课搭贺程名',AVG (c.Grade) '分数' from Student a, course b, sc c where a.Sno=c.Sno and b.Cno=c.Cno group by a.Sname,b.Cname
㈣ Sql每个班级课程平均成绩
1. 一张学生成绩表内SQL查询每个班级每门课程的平均分
select avg(分数) as 平均分, rtrim(cast(sum(case when 分数>=60 then 1 end)/count(*)*100 as char(10)))+'%' as 及格率 from A group by 班级,课程
2. sql题 查询每位同学的课程门数、总成绩、平均成绩”的SQL语句是什么
selectavg(成绩字段)平均成绩,sum(成绩字段)总成绩,count(课程字段)课程门数from表groupby学生字段;
3. 如何用SQL语句查询各门课程的平均成绩
创建表：
SET ANSI_NULLS ONGOSET QUOTED_IDENTIFIER ONGOSET ANSI_PADDING ONGOCREATE TABLE [dbo].[stuscore]
( [name] [varchar](50) COLLATE Chinese_PRC_CI_AS NULL,
[subject] [varchar](50) COLLATE Chinese_PRC_CI_AS NULL,
[score] [int] NULL,
[stuid] [int] NULL)
ON [PRIMARY]
GO
SET ANSI_PADDING OFF
插入数据：
insert into dbo.stuscore values ('张三','数学',89,1)；
insert into dbo.stuscore values ('张三','语文',80,1)；
insert into dbo.stuscore values ('张三','英语',70,1)；
insert into dbo.stuscore values ('李四','数学',90,2)；
insert into dbo.stuscore values ('李四','语文',70,2)；
insert into dbo.stuscore values ('李四','英语',80,2)；
查询结果如下：
列出各门课程的平均成绩：
select subject,AVG(score)平均成绩 from stuscore
group by subject;
4. SQL查询语句，要得到每个班每门课程的平均分，以及每个班的人数。如图：
select 班级,avage(语文) as 语文,avage(数学) as 数学,count(*) as 人数 from table groub by 班级
5. sql 查询每个班级每门课程选课人数和平均分
select class,cname,count(sno) as '选课人数',avg(grade) as '平均版分权'
from student a join sc b on a.sno=b.sno join course c on b.cno=c.cno
group by class,cname
6. 查询每位同学的课程门数、总成绩、平均成绩”的SQL语句是什么
SQL语句如下：
SELECT 学号, Count(课程编号) AS 课程总数, Sum(成绩) AS 总分数, Avg(成绩) AS 平均分
FROM 成绩表
GROUP BY 学号;
SQL常用操作语句如下：
选择：select * from table1 where 范围
插入：insert into table1(field1,field2) values(value1,value2)
删除：delete from table1 where 范围
更新：update table1 set field1=value1 where 范围
查找：select * from table1 where field1 like ’%value1%’
排序：select * from table1 order by field1,field2 [desc]
总数：select count as totalcount from table1
求和：select sum(field1) as sumvalue from table1
平均：select avg(field1) as avgvalue from table1
最大：select max(field1) as maxvalue from table1
最小：select min(field1) as minvalue from table1
7. 用SQL查询,某门课程每个班的总平均分（从高到低排列）
SELECT
AVG(数学）from
分数表
group
by
班级
order
by
AVG(数学）DESC
希望是满意答案，急需！！！！！！！！谢谢
8. SQL求每个学生平均成绩
select student.学号,student.姓名, course.课程名,(select avg(sc.成绩版) from sc where sc.学号权=student.学号) as 平均成绩 from student inner join sc on student.学号=sc.学号 inner join course on sc.课程号=course.课程号
9. SQL问题:如何分别给每个班算平均分
select 班级,avg(table.科目1) as 别名 ,avg(table.科目2) as 别名2,...,
from 表名
group by 班级
SQL查询语句，要得到每个班每门课程的平均分，专以及每属个班的人数
select 班级,avage(table.科目) as 别名,avage(科目2) as 别名2,count(*) as 人数 from table groub by 班级
㈤ 求一条sql语句！
我提供的思路如下：
select 成绩 from A a1 where name = '张三' and 成绩
in (select 成绩昌扰 from A a2 where name = '耐肆旦李四')
思路就是外层查询雹银出所有张三的成绩，再在这个集合中通过子查询出李四的成绩来进行筛选，选出来在张三成绩集合中存在且又在李四成绩集合中存在的成绩
㈥ 用sql命令 写出以下各题的命令
三、按要求写出以下各小题的SQL命令
1、使用UPDATE命令计算机每位学生的总成绩。
update xscj set count=fox+sx+english
2、使用SELECT命令查询所有男生的平均成绩。
select xh,count/3 as 平均成绩 from xscj where xh in( select xh from xs where xb='男')
3、使用INSERT命令向表XS插入一条记录，对应字段的值分别为：“090213”、“张三”、“男”、｛^1989-09-01｝、“共青团员”、120。
insert into xs values("090213","张三","男",{^1989-09-01},"共青团员",120)
4、使用SELECT命令对表XSCJ的总成绩字段进行升序排序。
select * from xscj order by count asc
5、使用SELECT命令对表XS按性别分组。
select * from xs group by xb
6、使用SELECT命令查询总成绩大于400分的学生的学号、姓名、性别以及总成绩，并将查询结果保存到数据表TEMP中。
select xh,xm,xb,count from xs,xscj where xs.xh=xscj.xh and count>400 into table temp
四、设XS表中已输入了若干条记录，请写出完成如下操作的VFP命令。
1、将表中第3至5条记录的出生日期（CSRQ）都增加三天
use xs
go 3
replace next 3 csrq with csrq+3
2、给表中最后5条记录中总学分低于30的记录加上删除标记
use xs
go reccount()-4
delete next 5 for zxf<30
3、以学号（XH）为关键字为表创建普通索引XH.CDX，并将其设为主控索引
use xs
index on xh tag xh of xh
set order to tag xh
4、用物理删除姓名为“刘燕”的记录
use xs
delete for xm='刘燕'
pack
5、给表中第3条记录后添加一条空白记录
use xs
go 3
insert blank
6、查看表中第3至8号记录的姓名、总学分
use xs
go 3
list next 6 fields xm,zxf
㈦ 1查询成绩表的总分数，平均分，最低分和最高分。用sql语句怎么写
---1. 计算每个人的总成绩并排名（要求显示字段：姓名，总成绩）
select name,sum(cast(score as bigint)) as allscore from stuscore group by name order by allscore desc
---2. 计算每个人的总成绩并排名（要求显示字段: 学号，姓名，总成绩）
select stuid,name,sum(cast(score as bigint)) as allscore from stuscore group by stuid,name order by allscore desc
---3. 计算每个人单科的最高成绩(要求显示字段: 学号，姓名，课程，最高成绩)
SELECT t1.stuid,t1.name,t1.subject,t1.score from stuscore t1,(SELECT stuid,max(score) as maxscore from stuscore group by stuid) t2 where t1.stuid=t2.stuid and t1.score=t2.maxscore
---4. 计算每个人的平均成绩（要求显示字段: 学号，姓名，平均成绩）
select distinct t1.stuid,t1.name,t2.avgscore from stuscore t1,(select stuid,avg(cast(score as bigint)) as avgscore from stuscore group by stuid) t2 where t1.stuid=t2.stuid
---5. 列出各门课程成绩最好的学生(要求显示字段: 学号，姓名,科目，成绩)
select t1.stuid,t1.name,t1.subject,t2.maxscore from stuscore t1,(select subject,max(score) as maxscore from stuscore group by subject) t2 where t1.subject=t2.subject and t1.score=t2.maxscore
---6. 列出各门课程成绩最好的两位学生(要求显示字段: 学号，姓名,科目，成绩)
select distinct t1.* from stuscore t1 where t1.stuid in(select top 2 stuscore.stuid from stuscore where subject = t1.subject order by score desc)order by t1.subject
---7. 统计报表(要求显示字段: 学号，姓名，各科成绩，总分，平均成绩)
select stuid as 学号,name as 姓名,sum(case when subject='语文' then score else 0 end) as 语文,sum(case when subject='数学' then score else 0 end) as 数学,sum(case when subject='英语' then score else 0 end) as 英语,sum(cast(score as bigint)) as 总分,(sum(cast(score as bigint))/count(*)) as 平均分 from stuscore group by stuid,name order by 总分 desc
---8. 列出各门课程的平均成绩（要求显示字段：课程，平均成绩）
select subject,avg(cast(score as bigint)) as avgscore from stuscore group by subject
---9. 列出数学成绩的排名（要求显示字段：学号，姓名，成绩，排名）
select * from stuscore where subject ='数学' order by score desc
---10. 列出数学成绩在2-3名的学生（要求显示字段：学号，姓名,科目，成绩）
select t3.* from(select top 2 t2.* from (select top 3 name,subject,score,stuid from stuscore where subject='数学' order by score desc) t2 order by t2.score) t3 order by t3.score desc
---11. 求出李四的数学成绩的排名
declare @tmp table(pm int,name varchar(50),score int,stuid int)
insert into @tmp select null,name,score,stuid from stuscore where subject='数学' order by score desc
declare @id int
set @id=0;
update @tmp set @id=@id+1,pm=@id
select * from @tmp where name='李四'
---12. 统计各科目及格人数
select subject,
(select count(*) from stuscore where score<60 and subject=t1.subject) as 不及格,
(select count(*) from stuscore where score between 60 and 80 and subject=t1.subject) as 良,
(select count(*) from stuscore where score >80 and subject=t1.subject) as 优
from stuscore t1 group by subject
---13．统计如下：数学:张三(50分),李四(90分),王五(90分),赵六(76分)
declare @s varchar(1000)
set @s=''
select @s =@s+','+name+'('+convert(varchar(10),score)+'分)' from stuscore where subject='数学'
set @s=stuff(@s,1,1,'')
print '数学:'+@s
㈧ asp:查询每个学生的各科成绩，总分，平均分的sql语句
dim rs,sql,sql2,zt,ck,nf,xq,cx,bj,bjmc,info
nf="2016"
xq="春季学期"
cx="期中考试"
bjmc="小学2012级3班"
set rs=server.CreateObject("Adodb.Recordset")
sql="select zuohao,name,xjh,"
sql=sql&"sum(case when xueke='语文' then score else 0 end) as yuwen,"
sql=sql&"sum(case when xueke='数学' then score else 0 end) as shuxue,"
sql=sql&"sum(case when xueke='英语' then score else 0 end) as yingyu,"
sql=sql&"sum(case when xueke='综合' then score else 0 end) as zhonghe,"
sql=sql&"汪告弊sum(score) as zongfen,"
sql=sql&"sum(score)*1.0/4 as pjf"
sql=sql&" from score where nianfen='"&nf&"' and xueqi='"&xq&"'困族 and cixu='"&cx&"' and bjmc='"&bjmc&"友蚂' group by zuohao,name,xjh order by zongfen desc "
rs.open sql,conn,1,1
㈨ sql 语句计算学生总成绩
select
学生.学号
as
姓名,
sum(成绩.分数)
as
总分
from
学生
left
join
成绩
on
成绩.学号=学生.学号
group
by
学生.学号
完全手打，若有疑问直接留言，我会持续关注的，保证好评率~
㈩ 5道SQL的查询语句
假设以上纯启橘表名字做团为“成绩表”
1) SELECT 成绩表.名字,成绩表.科目,成绩表.成绩
FROM 成绩表 INNER JOIN
(SELECT 科目,MAX(成绩) AS 最高分
FROM 成绩表
GROUP BY 科目) 成绩表2 ON 成绩表.成绩=成绩表2.最高分 AND 成绩表.科目=成绩表2.科目
2)
SELECT 名字,科目,成绩
FROM 成绩表
WHERE 成绩<60
ORDER BY 名字,科目
3)
SELECT TOP 3 名字,科目,成绩
FROM 成绩表
WHERE 科目=N'科目名称'旁派
ORDER BY 成绩 DESC
4)
SELECT TOP 3 名字,SUM(成绩) AS 总成绩
FROM 成绩表
GROUP BY 名字
ORDER BY SUM(成绩) DESC
5)
SELECT 名字,AVG(成绩)
FROM 成绩表
GROUP BY 名字
HAVING AVG(成绩)<60